Is most efficient at heating water Essay

This was done by counting the number of dissimilar bonds broken i. e. C-H and using a data table to find proscribed the amount of postcode required. Secondly, I worked out(p) the force released by bonds existence made again by counting the bonds and using a data table. I subtracted the second number from the scratch line to work out the energy released by the alcohol. Methanol Balanced Equation CH3OH+1. 5O2CO2+2H2O Bonds grim east northeastrgy mandatory for Bond Breaking (kJ/mol) Bonds do strength Released from Bonds Made (kJ/mol).Total EneBonds Broken cogency Required for Bond Breaking (kJ/mol) Bonds Made muscle Released from Bonds Made (kJ/mol) Total Energy Used + 12383 kJ/mol Total Energy Released 15398 kJ/mol Total Molar Energy of Combustion.Heptanol Balanced Equation Bonds Broken Energy Required for Bond Breaking (kJ/mol) Bonds Made Energy Released from Bonds Made (kJ/mol)Total Energy Used + 14299 kJ/mol Total Energy Released.-Bonds Broken Energy Required for Bon d Breaking (kJ/mol) Bonds Made Energy Released from Bonds Made (kJ/mol) 1/mol Total Molar Energy of Combustion, ? H (kJ/mol) = +16215-20222= -4007 This data justifies my hypothesis. much energy is released as you go up the series of alcohols therefore the peeing will set off up by a given temperature with little alcohol creation burnt. GCSE CHEMISTRY COURSEWORK Obtaining While obtaining evidence I took into discover many safety points into consideration Safety goggles were worn at all times I stood up so I could quickly move out of the way if there were any spillages etc. I tucked my tie in my shirt to avoid it catching kindling I also made sure I took accurate readings by Stirring the body of water to maintain an even temperature Closing windows that might cause a draught Keeping the tin at the same elevation above the flame.Repeating anomalous results GCSE CHEMISTRY COURSEWORK Analysing To produce a chart of molecular circumstances versus enthalpy of combustion both th ese determine request to be calculated. Here is an example First, the energy released has to be calculated. This can be done using the following radiation pattern q=energy released m=mass of water (g) c=specific heat capacity of the liquid heated up up (4. 18J/g/i c for water) ?t=temperature change of water For my first piece of data this is how q would be calculated. Temperature Change 10. 5i c Mass of weewee 400g (remember that water has a mass of 1g per cm3) Using the formula q=4004. 1810. 5.Second, the molar heat of combustion must be calculated. This can be done using the following formula -q=total energy transferred to the water (negative because the reaction is exothermic) n=number of moles (weight difference/formula mass) x1000=convert Js to kJs Continuing with the same example Energy Released 17556J (this was worked out with the first equation) Weight Change 1. 20g Formula Mass 32g Using the formula ? HMy original hypothesis was that as you go up the series of alcohols, little of the alcohol will have to be burnt for the given temperature rise.My results proved this hypothesis. The graph shows strong positive correlation proving that less alcohol is required for the temperature rise as you go up the group. There are no anomalies, and there is hardly any splosh. When I compare my observational data with my theoretical value I can see that although my experimental determine follow the same trend, they show much less energy being given off per mole than the theoretical ones. This is because not all of the energy produced went into the water (explained in more than detail in the evaluation). GCSE CHEMISTRY COURSEWORK Evaluation.My experimental data agreed with the theoretically predicted values. When both sets of results were plotted onto a scatter graph, I could see that they both followed the same trend. However, the line representing the theoretically predicted values was lower down on the graph showing that the experimental values were lowe r than the predicted ones. This is because of the experimental errors detailed below. Reliability I believe my data to be genuine. There is hardly any scatter as the results were fill to the line, and there were no anomalies.The data was reliable enough to firmly bridge over my conclusion. The fact that there was not much scatter shows this. However, the data was reliable but inaccurate because of the problems outlined below. If the data obtained was completely accurate therefore it would be on the theoretical data line. Experimental errors It was impossible to depict all the energy of the burning alcohol, using our equipment, into the can. Some inevitably take flight around the can and into the room. This explains why our results showed slightly more alcohol needing to be burned than the theoretical amount.Sources of experimental error Not all heat getting into the water (most escaped around the can or heated up the can) Draughts blowing in from outside Modifications If I was to do this experiment again I might either use a distinct calorimeter than a tin can i. e. one that conducted heat into the water more efficiently or simply put a lid on the can and insulate it. I would also do the experiment in an environment out of the open air to stop air currents changing my results and to concentrate the heat onto the water, rather than the air around.Further Work I might do the same experiment but using alkanes or else of alcohols. I would investigate as to whether they produce the same trend as with alcohols and see whether they are more or less efficient. GCSE Chemistry Coursework 1 Show preview only The above preview is unformatted text This schoolchild written piece of work is one of many that can be found in our GCSE Patterns of Behaviour section.